To balance the board about its center with A = 300, B = 375, C = 600, how many inches should weight B be moved left?

• A. 10 inches left
• B. 15 inches left
• C. 20 inches left
• D. 25 inches left

Answer: (B)

To determine how many inches weight B should be moved left to balance the board around its center, we need to understand the concept of moments and how they create balance.

In this situation, we define the positions of weights A, B, and C in relation to a pivot point. The balance condition occurs when the sum of moments around the pivot is equal on both sides. The moment is calculated by multiplying the weight by its distance from the pivot.

Given the weights A = 300, B = 375, and C = 600, we can set a balance equation based on their distances from the pivot point. Let's assume weight A is on the left and weight C is on the right of the pivot.

When weight B is moved to the left, this distance adjustment changes the moment contributed by B. To find out how far to move weight B to achieve a balance, we set up the equation based on moments:

• The moment contributed by weight A plus the moment contributed by the adjusted position of weight B should equal the moment contributed by weight C.

Through the math, moving weight B left by 15 inches shifts its moment effectively enough to balance the moments created by weights A and C. This choice results in equal pressure on both sides of the